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Two baseball players hit 68 home runs combined last year. The first player hit 5 more home runs than twice the number of home runs the second player hit. How many home runs did each player hit?

Respuesta :

68=(5+2y) +y
63=3y
y=21
1st player hit 47 and 2nd player hit 21
26whitealissa

Answer:

Step-by-step explanation:

68=(5+2y) +y63=3yy=211st player hit 47 and 2nd player hit 21

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