Answer:
Equation of the line that it is perpendicular to y=7x-3 and passes through the origin is given by 7y + x = 0
Explanation:
We have equation of line , y =7x -3, comparing it with y = mx +c
So slope of line , m = 7
We know that the product of slopes of perpendicular lines = -1
So m*Slope of perpendicular line = -1
7* slope of perpendicular line = -1
slope of perpendicular line = -1/7
Given that the perpendicular line passes through origin (0,)0)
We also know that equation of a line passing though origin is given by the expression, y = mx
Here m = -1/7
So equation of perpendicular line, y = -x/7
or 7y + x = 0
Equation of the line that it is perpendicular to y=7x-3 and passes through the origin is given by 7y + x = 0
