Given rational expression is
[tex]-\frac{8x}{8x^2+2x}[/tex]
Now we need to find the restricted values if any for this rational expression.
Restricted values means the possible values of the used variable (x) that will make denominator 0 as division by 0 is not defined.
So to find the restricted values, we just set denominator equal to 0 and solve for x
[tex]8x^2+2x=0[/tex]
[tex]2x(4x+1)=0[/tex]
2x=0 or 4x+1=0
x=0 or 4x=-1
x=0 or x=-1/4
Hence final answer is x=0, -1/4
