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I WILL GIVE BRAINLIEST!!! EASY POINTS

Drag an answer to each box to complete this paragraph proof.

Given: Triangle PQR with m∠P=(x)° , m∠Q=(3x)° , and m∠R=(5x)° .

Prove: x = 20

I WILL GIVE BRAINLIEST EASY POINTS Drag an answer to each box to complete this paragraph proof Given Triangle PQR with mPx mQ3x and mR5x Prove x 20 class=

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The answer for the first one is (x)°+(3x)°+(5x)°=180° and the answer for the second one is x=20. If you need me to explain how they got the answer, i'm here.

Answer:

Fill the blanks

1) (x)°+(3x)°+(5x)°=180°

2) x°=20°

Step-by-step explanation:

Consider the provided information.

Given: Triangle PQR with m∠P=(x)°, m∠Q=(3x)°, and m∠R=(5x)°.

We need to prove that x = 20

Consider the provided figure.

By the triangle sum theorem the sum of the angles in a triangle is equal to 180. Therefore using the give and triangle sum theorem,

m∠P+m∠Q+m∠R=180°

Now use substitution property.

(x)°+(3x)°+(5x)°=180°

Simplify the equation gets

9x°=180°

Finally, using the division property of equality.

9x°/9=180°/9

x°=20°

Hence proved

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