gabbywolfe2005 gabbywolfe2005
  • 10-10-2018
  • Mathematics
contestada

The perimeter of a rectangle is 50 meters. The width is five more than the length. Find the dimensions.

Respuesta :

oliviapamas05 oliviapamas05
  • 10-10-2018

P= 2L + 2 W = 50     P=50

W= L+ 5 Plug into equation (substitution)

2L +2 L+5 = 50

4L=50 -5

L= 45/4

L=11.25

P= 2 L + (2 L +5) = 50

P= 2(11.25) + 2(11.25) +5 =50

P=22.5 + 27.5

P=50     2L=22.5 and 2W= 27.5

L=11.25  W= 13.75


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