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A chemist is working on a reaction represented by this chemical equation:

FeCl2 + 2KOH → Fe(OH)2 + 2KCl.

If the chemist uses 4.15 moles of iron(II) chloride and 3.62 moles of potassium hydroxide, how many moles of iron(II) hydroxide will the reaction produce?

A. 1.81 mol
B. 3.62 mol
C. 4.15 mol
D. 7.24 mol

Respuesta :

Dejanras

Answer is: A. 1.81 mol.

Balanced chemical reaction: FeCl₂ + 2KOH → Fe(OH)₂ + 2KCl.

n(FeCl₂) = 4.15 mol; amount of iron(II) chloride.

n(KOH) = 3.62 mol; amount of potassium hydroxide, limiting reactant.

From chemical reaction: n(KOH) : n(Fe(OH)₂) = 2 : 1.

n(Fe(OH)₂) = n(KOH) ÷ 2.

n(Fe(OH)₂) = 3.62 mol ÷ 2.

n(Fe(OH)₂) = 1.81 mol; amount of iron(II) hydroxide.

ziocon5106

Answer:

It's A. 1.81 mol. This answer is on Plato.

#PlatoLivesMatter

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