Respuesta :
Vox = ?
Voy = 0 m/s
g = 9.8 m/s
s = 61.7 m
h = 42.4 m
(1)-----------------------------------...
To find the time taken for the ball to travel to the bottom:
For constant acceleration,
s = Voy*t + 0.5*g*t^2
42.4 = 0 + 0.5(9.8)*t^2
t^2 = 42.4 / 4.9
t^2 = 8.6531
t = 2.9417s
(2)-----------------------------------...
For the intial velocity of the horizontal component (Vox) of the ball:
s = Vox*t + 0.5*a*t^2
There is no force acting on the horizontal component, so there is no acceleration.
s = Vox*t
61.7 = 2.9417*Vox
Vox = 181.5029 m/s
(3)-----------------------------------...
Since there is no acceleration acting on the horizontal component, x, it remains constant throughout.
Hence, it is still 181.5029 m/s.
For the final velocity of the vertical component (Vfy) of the ball:
(Vfy)^2 = (Voy)^2 + 2*a*h
Acceleration in this case is the force of gravity.
(Vfy)^2 = 0 + 2*(9.8)*(42.4)
(Vfy)^2 = 831.04
Vfy = 28.8278 m/s
I've clearly explained every step. Hope that answers your question! =D
Answer:
the speed of the ball just before it will be equal to 41.75 m/s
Explanation:
data provided:
h = height of building = 89 m
L = horizontal distance = 80 m
The speed of the ball at maximum height is assumed to be equal to zero. If we use the equation of motion we have:
s = u*t + (a*t^2)/2, where s = distance; u = initial velocity; a = gravity acceleration; t = time
replacing values and clearing t:
t = ((89*2)/9.8)^1/2 = 4.26 s
the speed will be equal to:
vy = uy + a*t = g*t = 9.8*4.26 = 41.75 m/s
