Respuesta :

the answer is
[tex]3 {x}^{2} - 19x - 14[/tex]
first you must multiply or use the FOIL method (First, Outer, Inner, Last)
First you multiply the first terms
[tex](3x)(x)[/tex]
this gives you 3x^2, then you multiple the outer terms
[tex] ( - 7)(3x)[/tex]
this gives you -21x, then you multiply the inner terms
[tex](2)(x)[/tex]
that gives you 2x, finally you multiply the last terms
[tex](2)( - 7)[/tex]
that gives you 14, now you combine like terms
[tex] - 21x + 2x = - 19x[/tex]
now you put all the terms together and end up with your solution
[tex]3 {x}^{2} - 19x - 14[/tex]

Remember to follow the FOIL method.

Note that: FOIL = First, Outside, Inside, Last.

Multiply

First: (3x)(x) = 3x²

Outside: (3x)(-7) = -21x

Inside: (2)(x) = 2x

Last: (2)(-7) = -14

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3x² -21x + 2x -14

Combine like terms

3x² (-21x + 2x) - 14

3x² - 19x - 14

3x² - 19x - 14 is your answer

~Rise Above the Ordinary