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I need help with my chemistry homework. SHOW WORK

1) The density of tin (Sn) is the 5.75 g/cm^3. How many cubic decimeters (dm^3) does 17.2 kg of Sn occupy?

2) If half a liter (500 mL) of olive oil weights 425g, what is its density?

3) The density of silver is 10.5 g/cm^3. What is the mass of 0.987 dm^3 of silver ?

Respuesta :

nuconteaza119

d=density, m=mass, v=volume

1. 17.2kg=17200g

so knowing that d=m/V, use V=m/d to calculate the volume

v=17200/5.75

and then devide by 1000 to convert cm3 to dm3 and the answer will be in dm3

2. d=m/v

v=0.5l

m=425g

so use the formula and you will get d=425/0.5=850g/l

3. use d=m/v again, but not before rewriting the formula for volume: m=vd and  convert dm3 to cm3

1dm3=1000cm3

so 0.987dm3 =987 cm3

now m=987cm3 * 10.5g/cm3 and the answer will be in grams

The volume occupied by 17.2 kg of tin is 2.99 cubic decimeters.

The density of olive oil is 0.850 g/mL.

The mass of 0.987 cubic decimeters of silver is 10,365.5 grams.

Explanation:

Given:

  1. The density of tin is [tex]5.75 g/cm^3[/tex]
  2. A 500 mL of olive oil weighs 425 g.
  3. The density of silver [tex]10.5 g/cm^3[/tex]

To find:

  1. The volume in cubic decimeters of 17.2 kg of tin.
  2. The density of olive oil.
  3. Mass of [tex]0.987 dm^3[/tex] of silver

Solution:

1.

The mass of tin = m = 17.2 kg

[tex]1 kg = 1000 g\\m=17.2 kg=17.2\times 1000 g=17,200 g[/tex]

The volume of tin = v

The density of tin = d = [tex]5.75 g/cm^3[/tex]

[tex]d=\frac{m}{v}\\\\5.75g/cm^3=\frac{17,200 g}{v}\\\\v=\frac{17,200 g}{5.75g/cm^3}=2,991.3 cm^3\\\\1 cm^3= 0.001 dm^3\\\\v=2,991.3 cm^3=2,991.3\times 0.001 dm^3\\\\=2.9913 dm^3\approx 2.99 dm^3[/tex]

The volume occupied by 17.2 kg of tin is 2.99 cubic decimeters.

2.

The mass of an olive oil = m = 425 g

The volume of an olive oil = v = 500 mL

The density of an olive oil =d

[tex]d=\frac{m}{v}\\=\frac{425 g}{500 mL}=0.850 g/mL[/tex]

The density of olive oil is 0.850 g/mL.

3.

The mass of silver = m =

The volume of silver = v = [tex]0.987 dm^3[/tex]

[tex]1 dm^3=1000 cm^3\\v=0.987 cm^3=0.987\times 1000=987 cm^3[/tex]

The density of silver = d =[tex]10.5 g/cm^3[/tex]

[tex]d=\frac{m}{v}\\\\10.5 g/cm^3=\frac{m}{987 cm^3}\\\\m=10.5 g/cm^3\times 987 cm^3=10,365.5 g[/tex]

The mass of 0.987 cubic decimeters of silver is 10,365.5 grams.

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