Sanjay begins to correctly graph the function f(x) = (x + 1)2 – 3. Based on the axis of symmetry and the vertex, which graph could be Sanjay’s?
A.




For this case, the generic equation of a vertex shaped parabola is given by:
[tex]y = a (x-h) ^ 2 + k\\[/tex]
Where the vertex coordinates are (h, k)
Comparing with the given equation:
[tex]f (x) = (x + 1) ^ 2 - 3\\[/tex]
It is observed that h = -1 and k = -3 to obtain the form of the generic equation.
To find the axis of symmetry we derive the given function:
[tex]f '(x) = 2 (x + 1)\\[/tex]
We equate this derivative to zero and clear the value of x
[tex]2 (x + 1) = 0\\[/tex]
[tex]x = -1\\[/tex]
Therefore the vertice of the parabola is:
[tex](h, k) = (-1, -3)\\[/tex]
And the axis of symmetry is:
[tex]x = -1\\[/tex]
Answer:
Graphic 3
The graph third represents the vertex and axis of symmetry of the function f(x) = (x + 1)² - 3 option third is correct.
Any function of the form [tex]\rm f(x) =ax^2+bx+c[/tex] where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic function.
We have a function:
f(x) = (x + 1)² - 3
The above function is a quadratic function or parabolic function.
The vertex form of the function:
f(x) = (x - h)² + k
On comparing:
h = -1, k = -3
(h, k) = (-1, -3) is the vertex of the function.
Axis of symmetery:
x + 1 = 0
x = -1
Thus, the graph third represents the vertex and axis of symmetry of the function f(x) = (x + 1)² - 3 option third is correct.
Learn more about quadratic function here:
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