Answer:
Total time taken to travel 100 m = 23.82 seconds
In first case the velocity is constant and in the second case velocity is reducing by 0.2 m/s each second, so time taken will be different.
Explanation:
A go-cart travels the first half of a 100m track with a constant speed of 5.00m/s
Time taken for first half of 100m = Distance velocity = 50/5 = 10 seconds
We have equation of motion [tex]s=ut+\frac{1}{2} at^2[/tex], where s is the displacement, u is the initial velocity, t is the time taken and a is the acceleration.
For the second half of 100m we have
s = 50 m, u = 5 m/s, a = [tex]-0.200m/s^2[/tex]
Substituting
[tex]50=5t-\frac{1}{2} *0.2*t^2\\ \\ 0.1t^2-5t+50=0\\ \\ t^2-50t+500=0[/tex]
t = 13.82 seconds or t = 36.18 seconds
So it will take 13.82 seconds to travel second 50m
Total time taken = 10 + 13.82 = 23.82 seconds
In first case the velocity is constant and in the second case velocity is reducing by 0.2 m/s each second, so time taken will be different.
