Respuesta :
The number of the offspring produced in the dihybrid cross is 192.
In dihybrid cross, the ratio of the plants obtained in the F2 generation is 9: 3: 3: 1.
Thus, yellow round offspring is 9/16, green round offspring is 3/16, yellow wrinkled offspring is 3/16, and green wrinkled offspring is 1/16.
Thus, the number of green and round offspring produced can be calculated as:
Green round seed = 3/16
= 3/16 × 192
= 576/16
= 36
Thus, out of 192 peas, 36 will be green and round.
Suppose the parents indicated in the interactive produced 192 peas. Then the expected number of green and round offspring is thirty-six.
Further Explanation:
A recessive trait is defined as a trait that gets expressed by an individual when they show a homozygous recessive condition. This means that if an individual showing a recessive trait will definitely possess both the recessive alleles for that trait as a recessive trait gets concealed by the presence of allele for the dominant trait.
The monohybrid cross is an experiment between the first generation organisms that differ in only one trait. The resultant ratio of the f-1 generation is 1:2:1. A Punnett square mainly used to predict the possible genetic outcomes of a monohybrid cross. Mainly the dihybrid cross occurs when there are two traits are present.
The total number of offspring produced in the dihybrid cross is 192. In the dihybrid cross, the ratio of the plants obtained in the F-2 generation is 9:3:3:1.
Now, yellow round offspring is 9/16
Green round offspring is 3/16
Yellow wrinkled offspring is 3/16
Green wrinkled offspring is 1/16.
Thus, the number of green and round offspring produced can be calculated as:
Green round seed = 3/16
= 3/16 × 192
=576/16
= 36
Thus, out of 192 peas, 36 will be green and round.
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Answer Details:
Grade: High School
Subject: Biology
Chapter: Mendelian Inheritance
Keywords:
Generation, plant, pea, monohybrid, dihybrid, cross, offspring, trait, present, green, round, yellow, wrinkled, dominant, recessive.
