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Which line is a graph of the equation: 2x + 5y = 10?
Number graph ranging from negative five to five on the x axis and negative six to two on the y axis. Four lines are drawn in blue on the graph. Lines a and c have a positive slope and are parallel to each other. Lines b and d have a negative slope and are parallel to each other. Lines a and b intersect at (zero, two), and lines c and d intersect at (zero, negative two).
A. line a B. line b C. line c D. line d

Respuesta :

Answer: The equation is of line "b"


Step-by-step explanation:


First we find the slope of the given line by using slope intercept form.


Converting the equation into slope intercept form


[tex] 5y=-2x+10 [/tex]


Divide both side by 5 we get


[tex] y= \frac{-2}{5} x+ 2 [/tex]


On comparing with


[tex] y =mx+c [/tex]


We get slope [tex] m=\frac{-2}{5} [/tex]


as the slope of line is negative therefore the line will be either line "b" or line "d"


As line "b" pass from (0,2)


On putting point [tex] x=0 &y=2[/tex] in given equation we get


[tex] 2(0)+5(2)=0+10=10 [/tex]



Which is equal to RHS of the line


Therefore the given equation is of line "b"


Now putting point (0,-2)


We get [tex] 2(0)+5(-2)=-10 [/tex]


Which is not equal to RHS and therefore line "d" is not the required line



Therefore the given equation is of line "b"


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