PLEASE HELP SOON WILL MARK BRAINLIEST Write the equation of the line parallel to the given line and passing through the given point. y=1/3x−1 through (6,3)

Respuesta :

Answer:

y = (1/3)x + 1


Step-by-step explanation:

I'll assume that you meant y = (1/3)x - 1.  This line has the slope 1/3.  Write out the stope-intercept form y = mx + b and subst. (1/3) for m, 3 for y, 6 for x and calculate b:

3 = (1/3)(6) + b, or 3 = 2 + b.  Thus, b = 1, and we have the new equation

y = (1/3)x + 1.  This is parallel to y = (1/3)x - 1 and passes thru (6,3):  3 = (1/3)(6) -1 is true.


Answer:

y = (1/3)x + 1

Step-by-step explanation:

here