A bag contains 25 tickets, each colored either red or yellow. Red tickets are worth $0.50, and yellow tickets are worth $5.00. If the expected value of a ticket drawn at random from this bag is $3.20, how many of the tickets are red?

The answer to the question is 10, I just need an explanation why.

Respuesta :

i would like one to. i came up with 6

Answer:

10 red tickets

Step-by-step explanation:

Let us call x the number of red tickets.  

Notice since there are 25 tickets in the bag then we have 25-x yellow tickets.

Now, the probability of drawing a red ticket would be:

[tex]\displaystyle \frac{x}{25}[/tex]

And the probability of drawing a yellow ticket would be:

[tex]\displaystyle \frac{25-x}{25}[/tex]

Then we multiply each probability by their values and sum up to get the expected value, so that we get the equation:

[tex]\displaystyle 0.50\cdot\frac{x}{25}+5.00\cdot\displaystyle \frac{25-x}{25}=3.20[/tex]

We solve it like this:

Multiply both sides by 25 to clear of fractions:

[tex]0.5x+5(25-x)=80[/tex]

Distribute:

[tex]0.5x+125-5x=80[/tex]

Combine like terms:

[tex]-4.5x+125=80[/tex]

Subtract 125 from both sides:

[tex]-4.5x=-45[/tex]

Divide both sides by -4.5

[tex]x=10[/tex]

There are 10 red tickets in the bag.