Respuesta :
How to get answer:
[tex]\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=2,\:b=10,\:c=x\\=2\cdot \:10-2x\\\mathrm{Multiply\:the\:numbers:}\:2\cdot \:10=20\\=20-2x\\=20-2x-14\\Group\:like\:terms\\=-2x+20-14\\\mathrm{Add/Subtract\:the\:numbers:}\:20-14=6\\Answer: =-2x+6[/tex]
Hello!
Answer: ⇒⇒⇒⇒ -2x+6
Step-by-step explanation:
First expand.
[tex]2(10-x)[/tex]
Apply the distributive law.
[tex]a=2, b=10, c=x[/tex]
[tex]2*10-2x[/tex]
Multiply by the numbers.
[tex]2*10=20[/tex]
[tex]20-2x[/tex]
[tex]=20-2x-14[/tex]
Simplify.
Group like terms.
↓↓↓↓↓↓↓↓
[tex]-2x+20-14[/tex]
Add and subtract by the numbers.
[tex]=-2x+6[/tex]
[tex]=-2x+6[/tex]
Hope this helps!
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-Charlie