Answer:
0.2247,-2.2247
Step-by-step explanation:
Equation : [tex]2x^2+4x-1 =0[/tex]
We are supposed to find the values of x .
General form of equation : [tex]ax^2+bx+c=0[/tex]
Formula : [tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
a = 2
b = 4
c = -1
So, [tex]x=\frac{-4 \pm \sqrt{4^2-4(2)(-1)}}{2(2)}[/tex]
[tex]x=0.2247,-2.2247 [/tex]
Hence the values of x are 0.2247,-2.2247