Answer:
Coordinates of vertices of rectangle A B CD are A(1,11), B(3,1).
Equation of line AB is
[tex]\frac{y-1}{x-3}=\frac{1-11}{3-1}[/tex]
[tex]\frac{y-1}{x-3}=-10/2[/tex]
⇒y-1=-5(x-3)
⇒y-1= -5 x+15
⇒y+ 5 x=1+15
⇒y+5 x=16→[ Equation of line that contains line segment AB]
Equation of line perpendicular to AB is
x- 5 y +k=0
Since it passes through A(1,11).
1-5×11+k=0
1-55+k=0
k-54=0
k=54
So equation of AB is
x-5 y+ 54=0
So equation of line, containing line segment AD is
→x-5 y+54=0
