worth 35 points 1-8 Determine if the following equations have one solution, no soution, or infinite solution

A linear equation has infinite solutions if the left and right sides are the same. These equations can be manipulated into the expression 0=0, which is true no matter which value we choose for x, so they have infinite solution.
It has no solutions if the terms involving x cancel out, but the constant terms are different. These equations can be turned into an expression like [tex] a=b [/tex], where a and b are actually different numbers, and so it can never be true.
In all other cases, you have exactly one solution.
1
[tex] 2x+2x+2=4x+2 \iff 4x+2=4x+2 \iff [/tex] infinite solutions
2
[tex] 3(x-1)=2x+9 \iff 3x-3 = 2x+9 \iff x=12 [/tex]
3
[tex] 2x+8=2(x+4) \iff 2x+8=2x+8\iff[/tex] infinite solutions
4
[tex] 8(x+2)=2x+16 \iff 8x+16=2x+16 \iff 6x=0 \iff x=0 [/tex]
5
[tex] 4x+1 = 2(2x+3) \iff 4x+1 = 4x+6 \iff 1=6 \iff [/tex] no solutions
6
[tex] -2(x+1) = 2(x-1) \iff -2x-2=2x-2 \iff 4x=0 \iff x=0 [/tex]
7
[tex] 3x+1=3(x-1)+4 \iff 3x+1=3x-3+4 \iff 3x+1=3x+1\iff[/tex] infinite solutions
8
[tex] \dfrac{1}{2}(2-4x)+2x=13 \iff 1-2x+2x=13 \iff 1=13 \iff [/tex] no solutions.
Answer:
A linear equation has:
Step-by-step explanation:
Equation: 2x + 2x + 2 = 4x + 2
Solution:
2x + 2x + 2 = 4x + 2
=4x + 2 = 4x + 2 Infinite solution.
=4x - 4x = 2-2
=0 = 0
Equation: 3(x - 1) = 2x + 9
Solution:
= 3(x - 1) = 2x + 9
=3x - 3 = 2x + 9
=3x - 2x = 9 + 3
=x = 12 One solution.
Equation: 2x + 8 =2(x + 4)
Solution:
2x + 8 = 2x + 8 Infinite solution.
Equation: 8(x+2) = 2x + 16
Solution:
= 8x + 16 = 2x +16
= 8x - 2x = 16 - 16
= 6x = 0
= x = 0 One solution.
Equation: 4x + 1 = 2(2x + 3)
Solution:
4x + 1 = 4x + 6
= 0 = 5 No solution.
Equation: -2(x+1) = 2(x-1)
Solution:
= -2x - 2 = 2x - 2
= -4x = 0
= x = 0/-4 = 0 One solution.
Equation: 3x + 1 = 3( x- 1) + 4
Solution:
=3x +1 = 3x - 3 +4
= 3x + 1 = 3x +1 Infinite solution.
Equation: 1/2 (2 - 4x) +2x = 13
Solution:
= 1 - 2x + 2x = 13
= 1 = 13 No solution.