contestada

Which function can be used to model the graphed geometric sequence?
f(x + 1) = ⅚ f(x)
f(x + 1) = 6/5f(x)
f(x + 1) = ⅚ ^f(x)
f(x + 1) = 6/5^f(x)

Respuesta :

Answer: The correct option is 1, i.e., [tex]f(x+1)=\frac{5}{6}f(x)[/tex].

Explanation:

The geometric sequence is in the form of,

[tex]a,ar,ar^2,ar^3,....[/tex]

Where, a is the first term of the sequence and r is the common ratio of the sequence.

It means the [tex]n_{th}[/tex] term of the sequence is defined as,

[tex]a_n=ar^{n-1}[/tex]

So the the [tex](n+1)_{th}[/tex] term of the sequence is defined as,

[tex]a_{n+1}=ar^n[/tex]

[tex]a_{n+1}=r(ar^{n-1})[/tex]

[tex]a_{n+1}=ra_n[/tex]

It means the geometric sequence is in the form of,

[tex]f(x+1)=rf(x)[/tex]

Where, r be any constant.

From the options only [tex]f(x+1)=\frac{5}{6}f(x)[/tex] is in the form of [tex]f(x+1)=rf(x)[/tex] with common ratio [tex]\frac{5}{6}[/tex].

Therefore, the function can be used to model the graphed geometric sequence is [tex]f(x+1)=\frac{5}{6}f(x)[/tex] .

A - f(x + 1) = ⅚ f(x)

Step-by-step explanation:

Right on the edge final!

I hope this helps!

- sincerelynini