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A girl's feet are negative 4 over 6 yards from the surface of a pool. A boy's feet are negative 1 over 6 yards from the surface of the pool. Determine whose feet are closer to the surface.

The girl's feet are closer to the surface of the pool because negative 4 over 6 > negative 1 over 6.
The boy's feet are closer to the surface of the pool because negative 4 over 6 < negative 1 over 6.
The girl's feet are closer to the surface of the pool because negative 4 over 6 < negative 1 over 6.
The boy's feet are closer to the surface of the pool because negative 4 over 6 > negative 1 over 6.

Respuesta :

kudzordzifrancis
The correct answer is B.

See diagram

EXPLANATION

Let us choose zero to be our reference point. That is zero is representing the surface of the pool.

Since

[tex]-\frac{1}{6}>-\frac{4}{6}[/tex]

Or

[tex]-\frac{4}{6}<-\frac{1}{6}[/tex]

[tex]-\frac{1}{6}[/tex]

will be closer to zero.

We were told that

[tex]-\frac{1}{6}[/tex]

is where the boy's feet are. Therefore his feet are closer to the surface of the pool than the girl's feet.

So the correct answer is

the second option
Ver imagen kudzordzifrancis

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