Respuesta :
let log2 32 = x
then 2^x = 32
but we know 2^5 = 32
therefore, x = 5
Answer:
[tex]log_{2}(32)=5[/tex]
Step-by-step explanation:
To simplify the [tex]log_{2}(32)[/tex] we can use the logarithmic base change property:
[tex]log_{a}(b) = \frac{log_{c}(b)}{log_{c}(a)}[/tex].
Where a, b and c are real numbers.
Then we can transform the base 2 log into a base 10 logarithm.
[tex]log_{2}(32) = \frac{log(32)}{log(2)}[/tex]
[tex]log_{2}(32) = \frac{1.505}{0.3010}[/tex]
[tex]log_{2}(32)=5[/tex]