Respuesta :

let log2 32 = x

then 2^x = 32

but we know 2^5 = 32

therefore, x = 5

Answer:

[tex]log_{2}(32)=5[/tex]

Step-by-step explanation:

To simplify the [tex]log_{2}(32)[/tex] we can use the logarithmic base change property:

[tex]log_{a}(b) = \frac{log_{c}(b)}{log_{c}(a)}[/tex].

Where a, b and c are real numbers.

Then we can transform the base 2 log into a base 10 logarithm.

[tex]log_{2}(32) = \frac{log(32)}{log(2)}[/tex]

[tex]log_{2}(32) = \frac{1.505}{0.3010}[/tex]

[tex]log_{2}(32)=5[/tex]