Respuesta :

a. 28.0 g N

b. 17.7 g CI

Work for A:

2.00 mol N x [tex]\frac{14.00 g N}{1.00 mol N} = 28.0 g N[/tex]

Work for B :

3.01 x [tex]10^{23}[/tex] atms [tex](\frac{1 mol }{ 6.022 }10^{23}  atms )[/tex][tex](\frac{35.45g}{1 mol } ) = 17.7 g[/tex]

Following are the calculation of the mass is grams:

For point a:

The mass of an atom could be estimated by multiplying the number of moles of a material by its molar mass.

Using formula:

[tex]\bold{moles\ N\times\frac{ grams\ N}{moles \ N}=grams\ N}[/tex]

According to the periodic table, nitrogen's molar mass is [tex]\bold{14.01 \ \frac{g}{mol}}[/tex]

[tex]\to \bold{2.00\ moles\ N \times\frac{14.01 g\ N}{1\ mole \ N}=28.02\ grams \ N}[/tex]

For point b:

In this, we use Avogadro's number to calculate the mass:

[tex]\to \bold{3.01\times 10^{23} \ atoms \times\frac{1 \ mol}{ 6.022\times 10^{23} \ } \ atoms\times \frac{35.45}{1 \ mol}=17.7\ grams }[/tex]

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