The net external force on the propeller of a 3.0 kg model airplane is 6.8 N forward.What is the acceleration of the airplane? Answer in units of m/s^2.

Respuesta :

The correct answer to the question is 2.27 [tex]m/s^2[/tex] i.e the acceleration of the body is 2.27 [tex]m/s^2[/tex] along the forward direction.

CALCULATION:

As per the question, the net external force on the propeller of model airplane F =  6.8 N.

The mass of the model air plane m = 3.0 kg

We are asked to calculate the acceleration of the air plane.

From Newton's second law of motion, we know that the net external force acting on a body is equal to the product of mass with acceleration of that body.

Mathematically force F = m × a

                                  ⇒  [tex]a=\ \frac{F}{m}[/tex]

                                          [tex]=\ \frac{6.8\ N}{3.0\ kg}[/tex]

                                          [tex]=\ 2.27\ m/s^2[/tex]                  [ans]

The direction of acceleration is along the direction of force. Hence, the acceleration of the propeller is 2.27 [tex]m/s^2[/tex] along forward direction.