Given that the line passes through two points
(-2,-2) and (x1,y1)
Equation in point slope form is
y-y1 = m(x-x1)
substitute for slope
Hence equation of the line = [tex]\frac{y2-y1}{x2-x1} =[tex]y-y1 = \frac{-2-y1}{-2-x1}(x-x1)[/tex]
Since we donot know the value of x1or y1 the equation would contain x1, y1 also as answer.
Answer in point slope form is
[tex]\frac{y2-y1}{x2-x1} =[tex]y-y1 = \frac{-2-y1}{-2-x1}(x-x1)[/tex]
