Respuesta :
In circular motion we know that there is two type of acceleration that Cheryl experience
1. Tangential acceleration
2. Centripetal acceleration
here given that
[tex]a_t = 3 m/s^2[/tex]
for centripetal acceleration we know that
[tex]a_c = \frac{v^2}{R}[/tex]
[tex]a_c = \frac{4^2}{2} = 8 m/s^2[/tex]
now we know that both centripetal acceleration and tangential acceleration is perpendicular to each other
so total acceleration is vector sum of both and given as
[tex]a_{net} = \sqrt{8^2 + 3^2} = 8.54 m/s^2[/tex]
so total acceleration is 8.54 m/s^2
The total acceleration will be 8.54 m/sec².The total acceleration is the result of tangential and centripetal acceleration.Cheryl’s total acceleration will be 8.54 m/sec².
What is centripetal acceleration?
The acceleration needed to move a body in a curved way is understood as centripetal acceleration.
The direction of centripetal acceleration is always in the path of the center of the course.
The given data in the problem;
[tex]\rm a_t= 3m/sec^2[/tex]
r is the radius= 2m
v is the linear speed = 4.0m/s
[tex]a_{net }[/tex] is the total acceleration
The centripetal acceleration is found by;
[tex]\rm a_c= \frac{v^2}{r} \\\\ a_c= \frac{4^2}{2} \\\\ \rm a_c= 8 \ m/sec^2[/tex]
The total acceleration is found by;
[tex]\rm a_{net }= \sqrt{8^2+3^2} \\\\ a_{net }=8.54\ m/sec^2[/tex]
Hence the total acceleration will be 8.54 m/sec².
To learn more about the centripetal acceleration refer to the link;
https://brainly.com/question/17689540
