Respuesta :
A mountaineer climbed 1000 feet at a rate of x feet/hour
1000 = x ( t 1 ) eq1
5000 = X ( t 2) eq2 ( he climbed additional at different rate )
the rate was 10 feet / hour less than twice the first rate
X = 2x - 10 eq3
take eq1 and eq 2
( total time = t 1 + t 2 = T)
T = 1000/x + 5000/X
but X = 2x-10
T = 1000/x + 5000/( 2x -10)
T = 1000/x + 5000/( 2(x-5))
T = 1000/x + 2500 / (x-5)
Answer:
[tex]\frac{1000}{x} +\frac{2500}{x-5}[/tex]
Step-by-step explanation:
Total time T = (distance 1)/ (speed 1) + (distance 2)/ ( speed 2)
Distance covered by the mountaineer = 1000 feet
Speed of climbing = x feet per hour
Time taken will be = [tex]\frac{1000}{x}[/tex]
Additional distance covered by him = 5000 feet
Speed to cover this distance = [tex]2x-10[/tex] or [tex]2(x-5)[/tex]
So, total time T = [tex]\frac{1000}{x} +\frac{5000}{2(x-5)}[/tex]
T = [tex]\frac{1000}{x} +\frac{2500}{x-5}[/tex]
