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Consider horizontal parallel plates with a fixed potential difference. The upper plate has a voltage difference of 30 V with the lower plate, and they are separated by 3 cm. You move the two plates carefully to a separation of 4 cm. What is the strength of the electric field between the plates?

Respuesta :

relation between potential difference and electric field is given as

[tex]E . d = \Delta V[/tex]

so here we know that

d = 3 cm

[tex]\Delta V = 30 V[/tex]

[tex]E \times 0.03 = 30[/tex]

[tex]E = 1000 N/C[/tex]

So now when plates are separated to 4 cm distance carefully

the potential difference between them will change but the electric field between them will remain constant

So at distance of 4 cm also the electric field will be E = 1000 N/C

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