Given:
Height of the mercury manometer, h = 23.6 cm
To determine:
The pressure of gas trapped in the closed-tube mercury manometer
Explanation:
In the case of a closed tube mercury manometer, the pressure of the gas is equal to the height difference of the mercury levels in the two arms of the manometer.
i.e. P(gas) = P(h)
in this case, h = 23.6 cm = 236 mm
i.e. Pgas = 236 mmHg
Since, 1 atm = 760 mmHg
The corresponding Pgas(atm) = 236 mmHg * 1 atm/760 mmHg = 0.311 atm
Ans: The pressure of the gas is 0.311 atm
