Respuesta :
Answer:- 0.143 M
Solution:- HCl and NaOH reacts in 1:1 mol ratio as shown in the below reaction:
[tex]HCl(aq)+NaOH(aq)\rightleftharpoons NaCl(aq)+H_2O(l)[/tex]
Let's calculate the initial moles of HCl and the moles of NaOH added to it:
[tex]250.mL(\frac{1L}{1000mL})(\frac{0.3molHCl}{1L})[/tex]
= 0.075 mol HCl
[tex]100.mL(\frac{1L}{1000mL})(\frac{0.25molNaOH}{1L})[/tex]
= 0.025 mol NaOH
Since they react in 1:1 mol ratio, 0.025 mol of NaOH will react with 0.025 moles of HCl.
Remaining moles of HCl = 0.075 - 0.025 = 0.050
Total volume of the solution = 0.250 L + 0.100 L = 0.350 L
So, the concentration of HCl in the resulting solution = [tex]\frac{0.050mol}{0.350L}[/tex]
= 0.143 M
Hence, the concentration of HCl acid in the resulting solution is 0.143 M.
