Respuesta :
The equation that shows the decomposition of silver carbonate are;
2Ag2CO3 ---------> 4Ag + 2CO2 + O2
From the periodic table:
Mass of silver = 107.8682 grams
Mass of carbon = 12 grams
Mass of oxygen = 16 grams
Molar mass of Ag2CO3 = 2(107.8682) + 12 + 3(16) = 275.7364 grams
From the balanced equation above:
2(275.7362) = 551.4728 grams of Ag2CO3 produces 4(107.8682) = 431.4728 grams of Ag
Thus, in order to know the mass of Ag produced from 2.76 grams of Ag2CO3, we'll use the cross multiplication method;
Mass of Ag produced = (2.76 × 431.4728) / (551.4728) = 2.16 grams
Based on the calculations demonstrated above, the law of conservation of mass is applied.
If an investigation starts with 2.76 g of silver carbonate and ends with only 2.16 g of silver without any other product, the law of conservation of mass does not hold true in such an investigation.
The law of conservation of mass which states that the total mass of a reaction in a closed system is conserved does not hold true for open systems.
In open systems, materials can be lost to or gained from the surroundings, unlike in closed systems. A gain of materials will result in mass increase while a loss of materials will result in a mass decrease.
If you heat silver carbonate till it decomposes, carbon dioxide and oxygen gases would be released according to the following equation:
[tex]2Ag_2CO_3 ---> 4Ag + 2CO_2 + O_2[/tex]
Thus, if the system is not closed, the gases would escape and there would be a loss in mass.
From the illustration, 2.76 g of silver carbonate started the reaction but only 2.16 g of silver residue was left at the end of the reaction.
Mass lost = 2.76 - 2.16
= 0.6 g
More on the law of conservation of mass can be found here: https://brainly.com/question/13383562