[tex]Solution, \mathrm{Expand}\:\left(x+2\right)\left(x-3\right):\quad x^2-x-6[/tex]
[tex]Steps:[/tex]
[tex]\left(x+2\right)\left(x-3\right)[/tex]
[tex]\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd,\\a=x,\:b=2,\:c=x,\:d=-3,\\xx+x\left(-3\right)+2x+2\left(-3\right)[/tex]
[tex]\mathrm{Apply\:minus-plus\:rules},\\+\left(-a\right)=-a,\\xx-3x+2x-2\cdot \:3[/tex]
[tex]\mathrm{Simplify}\:xx-3x+2x-2\cdot \:3,\\\mathrm{Add\:similar\:elements:}\:-3x+2x=-x,\\xx-x-2\cdot \:3,\\\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c},\\xx=\:x^{1+1}=\:x^2,\\x^2-x-2\cdot \:3,\\\mathrm{Multiply\:the\:numbers:}\:2\cdot \:3=6,\\x^2-x-6[/tex]
[tex]\mathrm{The\:Correct\:Answer\:is\:x^2-x-6}[/tex]
[tex]\mathrm{Hope\:This\:Helps!!!}[/tex]
[tex]\mathrm{-Austint1414}[/tex]
