Answer:
the second number is 60
Step-by-step explanation:
f= first s= second t=third
f+s+t=123
s=4f
t=s-12
lets get everything in terms of s
f=s/4
t=s-12
now plug those back into the original equation
(s/4)+s+(s-12)=123
add 12 to both sides and you get
(s/4)+2s=135
multiply everything by 4
s+8s=540
9s=540
s=60
The second number is 60.
Since all the numbers are relating to first number majorly, thus, let the first number be denoted as [tex]x[/tex].
Then we have:
Second number = [tex]4x[/tex]
Third number = Second number - 12 = [tex]4x - 12[/tex]
Since their sum is 123, thus we have:
[tex]\text{First number + Second number + Third number = 123}\\\\x + 4x + (4x - 12) = 123\\\\9x = 123 + 12 = 135\\\\x = \dfrac{135}{9}\\\\x = 15[/tex]
Since the second number is 4x, thus we have:
[tex]\text{Second number} = 4 \times x = 4 \times 15 = 60[/tex]
Similarly, the third number = second number - 12 = 48.
Thus, the needed value of second number is 60.
Learn more about algebraic equations here:
https://brainly.com/question/953809
