The length of a rectangle is 8 cm more than 3 times its width. The perimeter of the rectangle is 64 cm. Show the equation that would be used to find the dimensions of the rectangle.

Let w = the width. Then 3w = length + 8. So the equation is 64 = 2(3w – 8) + 2w.

Let w = the width. Then 3w + 8 = length. So the equation is 64 = 2(3w + 8) + 2w. 64 = 2(3w + 8) + 2w

Let w = the width. Then 3(w + 8) = length. So the equation is 64 = 2(3(w + 8)) + 2w.

Let w = the width. Then 3w + 8 = length. So the equation is 64 = (3w + 8) w.

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20plant 20plant · Answer 1 · 2018-11-07T04:23:14+01:00

Answer:

The correct answer should be B, Let w = the with. the 3w + 8 = length. so the equation is 64 = 2(3w + 8) + 2w. 64 = 2(3w + 8) + 2w

Step-by-step explanation:

Perimeter = Length+Length+Width+Width

The Length (L) is +8 cm bigger then the Width (w) *3

L = 3W+8

64 = (3W+8)+(3W+8)+W+W

64 = 2(3W+8)+2W

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