The slope of line is 0.
How to describe the problem ?
The general equation for a straight line is y=mx+c.
Here, the equation is x= -3, so comparing with the general equation we get y=0 here. So, we can say that, the line is parallel to y-axis, i.e. x=a.
The given line is a line parallel to y-axis, which is 3 units left from the origin.
What is the slope of the line ?
The slope of any line is m=[tex]tan\alpha[/tex], where m is slope and [tex]\alpha[/tex] is the angle of the line with x-axis.
The line perpendicular to the line x= -3 is parallel to the x-axis and makes angle 0° with the x-axis.
Here, [tex]\alpha[/tex] = 0°
∴ m = tan 0° = 0
The slope is 0.
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