Respuesta :
Given: an n-gon
Prove: The sum of the measures of the interior angles is 180(n – 2)°.
Complete the missing parts of the paragraph proof.
We are given an n-gon, which has n sides and n vertices.
Answers:
1. If we choose one of the vertices, we can draw n-3 diagonals.
2. These diagonals form n-2 triangles.
3. The sum of the interior angle measures of a triangle is 180 degrees.
4. n – 2 triangles would have an interior angle measure sum of 180 degrees.
5. Therefore, the sum of the measures of the interior angles of an n-gon is 180(n – 2)°.
The missing statements parts of the paragraph are as follows;
If we choose one of the vertices, we can draw n-3 diagonals.
These diagonals form n-2 triangles.
The sum of the interior angle measures of a triangle is 180 degrees.
n – 2 triangles would have an interior angle measure sum of 180 degrees.
Therefore, the sum of the measures of the interior angles of an n-polygon is 180(n – 2)°.
Given:
An n-polygon Prove: The sum of the measures of the interior angles is 180(n – 2)°.
What is a polygon?
The two polygons are similar, corresponding sides that have a constant value of their ratios.
We are given an n-polygon, which has n sides and n vertices.
The missing statements parts of the paragraph are as follows;
- If we choose one of the vertices, we can draw n-3 diagonals.
- These diagonals form n-2 triangles.
- The sum of the interior angle measures of a triangle is 180 degrees.
- n – 2 triangles would have an interior angle measure sum of 180 degrees.
Therefore, the sum of the measures of the interior angles of an n-polygon is 180(n – 2)°.
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