Greg is driving a remote control car at a constant speed. He starts the timer when the car is 5ft away after 2 seconds the car is 35ft away
Let x be the seconds and y be the feet the car is away
In 0 seconds the car is 5ft away. (0, 5)
In 2 second the car is 35 ft away (2, 35)
Question says constant speed
so we find linear equation y=mx+b
use the points (0,5) and (2,35)
slope [tex]m = \frac{y_2-y_1}{x_2-x_1} = \frac{35-5}{2-0}= 15[/tex]
y intercept is 5
so equation becomes y = 15x + 5
to find the distance the car has traveled after 10 secs
We plug in 10 for x and find out y
y = 15(10) + 5= 150+5= 155
the distance the car has traveled after 10 secs is 155 feet
