Answer:
6, 8, 10 and 12 years
Step-by-step explanation:
I guess you need to find their ages. This can be done by solving an algebraic equation as follows:
Let x years be the age of the youngest child. Then the ages of the other 3 are x+2, x+4 and x+6 years because they were born at 2 year intervals. So we have the equation:
x + x + 2 + x + 4 + x + 6 = 36
4x + 12 = 36
4x = 24
x = 6
so their ages are 6, 8, 10 and 12 years
