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Answer:
D. y + 3 = -12/7(x - 5)
Step-by-step explanation:
(5, -3) and (-2, 9)
slope = m = (9 - (-3))/(-2 - 5) = 12/(-7) = -12/7
Point slope form of the equation of a line:
y - y1 = m(x - x1)
We have slope = m = -12/7. We will use point (5, -3), so x1 = 5, and y1 = -3.
y - (-3) = -12/7(x - 5)
y + 3 = -12/7(x - 5)
The point-slope form:
[tex]y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (5, -3) and (-2, 9). Substitute:
[tex]m=\dfrac{9-(-3)}{-2-5}=\dfrac{12}{-7}=-\dfrac{12}{7}\\\\y-(-3)=-\dfrac{12}{7}(x-5)\\\\\boxed{y+3=-\dfrac{12}{7}(x-5)}[/tex]