A ball is fired with speed v = 180 m/s at an angle 40 degree
So here we can say the components of velocity is given as
[tex]v_{x} = 180 cos40 = 137.9 m/s[/tex]
[tex]v_y = 180 sin40 = 115.7 m/s[/tex]
now when ball will reach the maximum height its velocity in vertical direction will become zero
so here we can say
[tex]v_{fy} = 0[/tex]
now using kinematics we will have
[tex]v_{fy}^2 - v_y^2 = 2 a d[/tex]
[tex]0 - 115.7^2 = 2(-9.8)(H)[/tex]
so maximum height is
[tex]H = 683 m[/tex]
so it will reach at maximum height of 683 m
