sacrdancestor sacrdancestor
  • 07-11-2018
  • Mathematics
contestada

7+(53-3^{4} )/\sort{16}

Respuesta :

Professor1994 Professor1994
  • 07-11-2018

Answer: 7+(53-3^{4} )/sqrt{16} = 0


Solution:

7+(53-3^{4} )/sqrt{16} =

7+(53-3*3*3*3)/4 =

7+(53-81)/4 =

7+(-28)/4 =

7-7 =

0

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