Answer : The density of ammonia is 0.6464 g/L.
Solution : Given,
Temperature of ammonia = 293 K
Pressure of ammonia = 0.913 atm
Molar mass of ammonia = 17.031 g/mole
By using ideal gas law,
[tex]PV=nRT\\P=\frac{wRT}{MV} \\P=\frac{\rho RT}{M}\\\rho=\frac{PM}{RT}[/tex]
where,
P = pressure of gas
V = volume of gas
n = number of moles
T = temperature of gas
R = Gas constant = 0.0821 Latm/mole/K
[tex]\rho[/tex] = Density
[tex](Moles=\frac{Mass}{\text{ Molar mass}})[/tex] and [tex](Density=\frac{Mass}{Volume})[/tex]
Now put all given values in ideal gas law, we get
[tex]\rho=\frac{(0.913atm)\times (17.031g/mole)}{(0.0821Latm/mole/K)\times (293K)}=0.6464g/L[/tex]
Therefore, the density of ammonia is 0.6464 g/L.
