Respuesta :
Answer:- 64015 J
Solution: There is 4250 mL of water in the calorimeter at 22.55 degree C.
density of water is 1 g per mL.
So, the mass of water = [tex]4250mL(\frac{1g}{1mL})[/tex] = 4250 g
Final temperature of water after adding the hot copper bar to it is 26.15 degree C.
So, [tex]\Delta T[/tex] for water = 26.15 - 22.55 = 3.60 degree C
Specific heat for water is 4.184 [tex]\frac{J}{g.^0C}[/tex]
The heat gained by water is calculated by using the formula:
[tex]q=mc\Delta T[/tex]
where, q is the heat energy, m is mass and c is specific heat.
Let's plug in the values in the formula and do the calculations:
[tex]q=4250g*\frac{4.184J}{g.^0C}*3.60^0C[/tex]
q = 64015 J
So, 64015 J of heat is gained by the water.
The heat gained by the water when 85.2 g of copper is heated and placed in a coffee cup calorimeter containing 4250 mL of water is 64015.2 J
- To solve this question, we'll begin by calculating the mass of the water. This can be obtained as follow:
Density of water = 1 g/mL
Volume of water = 4250 mL
Mass of water =?
Mass = Density × Volume
Mass of water = 1 × 4250
Mass of water = 4250 g
- Next, we shall determine the change in the temperature of water.
Initial temperature (T₁) = 22.55 °C
Final temperature (T₂) = 26.15 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 26.15 – 22.55
ΔT = 3.6 °C
- Finally, we shall determine the heat gained by the water.
Mass of water (M) = 4250 g
Change in temperature (ΔT) = 3.6 °C
Specific heat capacity of water (C) = 4.184 J/gºC
Heat gained (Q) =?
Q = MCΔT
Q = 4250 × 4.184 × 3.6
Q = 64015.2 J
Therefore, the heat gained by the water is 64015.2 J
Learn more: https://brainly.com/question/134847
