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A child sitting 1.10m from the center of a merry-go-round moves with a speed of 1.25m/s. calculate (a) the centripetal acceleration of the child, and (b) the net horizontal force exerted on the child (mass=25.0 kg)

Respuesta :

cvgold11

(A) radius of merry go round is (r)=1.10m

velocity of merry go round is (v)=1.25m/v

1.25^2/1.10


(b) 25X1.42

Fr=35.5N

onyebuchinnaji

(a) The centripetal acceleration of the child is 1.42 m/s².

(b) The net horizontal force exerted on the child is 35.5 N.

The given parameters;

  • radius of the merry-go-round, r = 1.10 m
  • speed of the child, v = 1.25 m/s
  • mass of the child

The centripetal acceleration of the child is calculated as follows;

[tex]a_c = \frac{v^2}{r} \\\\a_c = \frac{1.25^2}{1.1} \\\\a_c = 1.42 \ m/s^2[/tex]

The net horizontal force exerted on the child is calculated as follows;

[tex]F = ma_c\\\\F = 25 \times 1.42\\\\F = 35.5 \ N[/tex]

Thus, the net horizontal force exerted on the child is 35.5 N.

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