Set up the inequality:
Add the part-timer's hours of 20
Full time hours is 40 times n employees
At least means greater than or equal to, so we use the >= sign
40n + 20 >= 260
Answer:
The inequality will be: [tex]40n+20\geq 260[/tex]
Tom must schedule at least 6 full-time employees.
Step-by-step explanation:
Each full-time employee works 40 hours per week.
If the number of full-time employees is [tex]n[/tex], then [tex]n[/tex] number of full-time employees work [tex]40n[/tex] hours per week.
Tom has one part-time employee who works 20 hours per week.
So, the total hours worked by all employees [tex]= (40n+20)[/tex] hours.
Given that, all his employees will work at least 260 person-hours per week.
So, the inequality will be: [tex]40n+20\geq 260[/tex]
Solving the above inequality.....
[tex]40n+20\geq 260\\ \\ 40n\geq 260-20\\ \\ 40n\geq 240\\ \\ n\geq \frac{240}{40}\\ \\ n\geq 6[/tex]
So, Tom must schedule at least 6 full-time employees.
