Given that Lindsay went for a drive. she used [tex]\frac{8}{3}[/tex] gallon of gas every [tex]\frac{4}{5}[/tex] of an hour. Now we need to solve for her gallons per hour.
To find value for 1 unit for any similar problem we just divide one quantity by another quantity
so we will use same logic here
[tex]\frac{4}{5}[/tex] of an hour uses [tex]\frac{8}{3}[/tex] gallon of gas
then 1 hour uses \frac{\left(\frac{8}{3}\right)}{\left(\frac{4}{5}\right)} gallon of gas
= [tex]\frac{8}{3}\cdot\frac{5}{4}[/tex]
= [tex]\frac{40}{12}[/tex]
= [tex]\frac{10}{3}[/tex]
Hence final answer is [tex]\frac{10}{3}[/tex] gallons per hour.
A = amount of gas used for the drive = 8/3 gallon
t = duration of time in which amount of gas A is used = 4/5 hours
r = rate of gas used
rate of use of gas is given as the ratio of gas used in the amount of time given.
hence , rate of gas used is given as
R = A/t
inserting the values given above
R = (8/3)/(4/5)
R = 8 x 5/(3 x 4)
R = 40/12
R = 3.33 gallons per hour
