you and a friend have a hula hoop competition. you win 3 out of every 7 trials. your friend wins 5 more trials than you. how many trials are in the competition?

Respuesta :

We have been given that me and my friend have a hula hoop competition. I win 3 out of every 7 trials. My friend wins 5 more trials than me.  

Probability of my winning is [tex]\frac{3}{7}[/tex] and probability of my friend's winning is [tex]\frac{4}{7}[/tex].    

Let there be n numbers of trials. Therefore, my score after n trials is [tex]\frac{3n}{7}[/tex] and my friend's score after n trials is [tex]\frac{4n}{7}[/tex].

Therefore, trials my friend won more than be would be,

[tex]\frac{4n}{7} -\frac{3n}{7} =\frac{n}{7}[/tex]

We have been given that my friend won 5 more trials than me. So upon equating these two quantities we will get,

[tex]\frac{n}{7}=5[/tex]

[tex]n=7\times 5=35[/tex]

Therefore, total number of trials is 35.

Let us verify our answer.

After 35 trials I will win [tex]35\times\frac{3}{7} =5\times3=15[/tex]trials and my friend will win [tex]35\times\frac{4}{7} =5\times4=20[/tex] trials. Hence, my friend won 5 more trials than me.