Respuesta :
We have been given an equation [tex]d=0.15t[/tex] that represents the distance an airplane travels in Miles (d) is related to the time in seconds (t).
A. Upon substituting t=1 in our equation we will get,
[tex]d=0.15\times 1[/tex]
[tex]d=0.15[/tex]
We can see that our plane is travelling at rate of 0.15 miles per second.
[tex]\text{Speed of plane }=0.15\frac{\text{miles}}{\text{second}}[/tex]
Therefore, plane is flying at the rate of 0.15 miles per second.
B. To find distance traveled by airplane in 30 seconds we will substitute t=30 in our given equation.
[tex]d=0.15\times 30[/tex]
[tex]d=4.5[/tex]
Therefore, plane will travel 4.5 miles in 30 seconds.
C. To find time it will take to travel 12.75 miles we will substitute d=12.75 in our given equation.
[tex]d=0.15\times t[/tex]
[tex]12.75=0.15\times t[/tex]
[tex]t=\frac{12.75}{0.15}=85[/tex]
Therefore, plane will take 85 seconds to travel 12.75 miles.
Answer:
The correct answers are [tex](A)\; 0.15\times1\; \frac{\rm{miles}}{\rm{second}} \;(B) \;4.5\;\rm{miles}\; (C) \;85\;\rm{seconds}[/tex]
Step-by-step explanation:
Given: An airplane is flying from New York city to Los Angeles.The distance it travels in Miles, [tex]D[/tex], is related to the time in seconds, [tex]T[/tex], by the equation [tex]d=0.15t[/tex].
According to the mentioned conditions in question,
[tex]A[/tex]. Substituting [tex]t=1[/tex] in our equation we will get,
[tex]d=0.15\times1\; \frac{\rm{miles}}{\rm{second}}[/tex]
Therefore, plane is flying at the rate of [tex]0.15[/tex] miles per second
[tex]B[/tex]. Distance travelled in [tex]30[/tex] seconds is calculated as [tex]d=0.15\times 30=4.5\; \frac{\rm{miles}}{\rm{second}}[/tex]
Therefore, plane will travel [tex]4.5[/tex] miles in [tex]30[/tex] seconds.
[tex]C[/tex]. Time taken by airplane to cover [tex]12.75\;\rm{miles}[/tex] is calculated as:
[tex]12.75=0.15\times{t}\\\frac{12.75}{0.15}=t\\[/tex]
[tex]t=85\; \rm{seconds}[/tex]
Therefore, plane will take [tex]85[/tex] seconds to travel [tex]12.75[/tex] miles.
Hence, the correct answers are [tex](A)\; 0.15\times1\; \frac{\rm{miles}}{\rm{second}} \;(B) \;4.5\;\rm{miles}\; (C) \;85\;\rm{seconds}[/tex]
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