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2c2h2(l) 5o2(g) yeild 4co2(g) 2h2o(g) if the acetylene tank contains 37.0 mol of c2h2 and the oxygen tank contains 81.0 mol of o2, what is the limiting reactant for this reaction?

Respuesta :

kenmyna

2C2H2(l)  +5O2(g)→ 4Co2(g)  + 2H2O

The   limiting  reactant  for reaction above is O2


explanation

 The limiting reagent is determined using mole ratio  of both reactant.

 that  is the  mole ratio  of  C2H2:O2  which is  2:5 .

 The mole ratio above  implies  that 37.0 mole  of C2H2   needs  37.0 moles  x5/2=92  moles of  O2.


Since the available moles of O2  was 81.0 mole  and 92  moles  are  required to completely  react with  C2H2 , O2   is  the limiting reagent.

nutboi

Answer:

o2

Explanation:

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