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A circle in the xy, y?Plane has the equation (x+92)^2+(y+54)^2=73(x+92) 2 +(y+54) 2 = 73, x, plus, 92, right parenthesis, start superscript, 2, end superscript, plus, left parenthesis, y, plus, 54, right parenthesis, start superscript, 2, end superscript, equals, 73. What is the length of the diameter of the circle?

Respuesta :

Iqta

According to our understanding your equation of circle can be written as:

[tex](x+92)^{2} +(y+54)^{2} = 73[/tex]

and if we compare it with the standard equation of circle

[tex](x-h)^{2}+ (y-k)^{2}= r^{2}[/tex]

Our radius will be

                  r= √73

           [tex]r = 8.54[/tex]

We know that diameter is double the radius of the circle

[tex]d = 2*r[/tex]

[tex]d = 17.08[/tex]

Hope it helps! :)



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